(i) Force F 1 = Area of triangle ADE X Width of tank The total pressure force consists of the following components: The pressure diagram is split into triangle ADE, rectangle BDEF and triangle EFC. Intensity of pressure at D, Pd = P1g x h = 900 x 9.81 x 0.9 = 7946.1 N/m 2 (a) Total pressure on one vertical side is calculated by drawing pressure diagram, which is shown in Fig.8-1 Given : Cubical tank of sides 1.5 m means the dimensions of the tank are 1.5 mx 1.5 mx 1.5 m.ĭensity of liquid, Pi = 0.9 x 1000 = 900 kg/m 3

(a) total pressure, and (b) position of centre of pressure. Calculate for one vertical side of the tank : The upper remaining part is filled with oil of specific gravity 0.9. It contains water for the lower 0.6 m depth. † † margin: y y x - 2 - 1 1 2 - 2 - 1 1 2 50 water line not to scale d ⁢ ( y ) = 50 - y Figure 6.5.8: Measuring the fluid force on an underwater porthole in Example 6.5.4.Q.8 A cubical tank has sides of 1.5 m. The truth is that it is not, hence the survival tips mentioned at the beginning of this section. This is counter-intuitive as most assume that the door would be relatively easy to open. Most adults would find it very difficult to apply over 500 lb of force to a car door while seated inside, making the door effectively impossible to open. Using the weight-density of water of 62.4 lb/ft 3, we have the total force as We adopt the convention that the top of the door is at the surface of the water, both of which are at y = 0. Its length is 10 / 3 ft and its height is 2.25 ft. SolutionThe car door, as a rectangle, is drawn in Figure 6.5.7.

Hydrostatic force on side of tank